The first three-digit number which is divisible by 3 is 102 . The last three-digit number which is divisible by 3 is 999 . The number of three-digit numbers divisible by 3 are 3999 − 3102 + 1 = 333 − 34 + 1 = 300 .
What is the largest three digit number which is exactly divisible by 3 4 and 5?
60 is the number which is exactly divisible by 3, 4 and 5.
What is a 3 digit number divisible by 3 and 5?
From 1 to 1000. Of the, 6 are two digit numbers. Therefore, the number of 3 digit numbers divisible by 3 and 5 are 66 – 6 = 60.
Which is the number divisible by 3?
As the divisibility rule of 3 states that a number is divisible by 3 only when the sum of individual digits is divisible by 3. So, the 4 different even digit numbers are divisible by 3 = set of (2, 4, 6, 0) and (8, 6, 4, 0).
What are the 3-digit numbers divisible by 7?
The greatest 3-digit number divisible by 7 is 994. Therefore the three-digit numbers are 105, 112, 119, 126,………….. 994. This is an Arithmetic progression with first term a=105, common difference d = 7, last term =994.
What are the divisibility rules for 3?
According to the divisibility rule of 3, a number is said to be divisible by 3 if the sum of all digits of that number is divisible by 3. For example, the number 495 is exactly divisible by 3. The sum of all digits are 4 + 9 + 5 = 18 and 18 is exactly divided by 3.
Which is exactly divisible by 3?
A number is divisible by 3, if the sum of its all digits is a multiple of 3 or divisibility by 3. Sum of all the digits of 54 = 5 + 4 = 9, which is divisible by 3. Hence, 54 is divisible by 3.
What is the smallest 3 digit number divisible by 3?
The sum of all 3-digit numbers divisible by 3 is 165150. What is the smallest three digit number divisible by 3? The smallest or lowest 3-digit number divisible by 3 is the first number on the list above (first 3 digit number divisible by 3). As you can see, that number is 102.
Are there any numbers that are divisible by 3, 4, 5 and 6?
I wrote down a 4-digit number that was divisible by 3, 4, 5 and 6, but I spilt a cup of tea on it and can only see the first two digits. The first two digits are 95 (in that order).
Which is divisible by 3 as the sum of its digits?
Similarly, 516 is divisible by 3 completely as the sum of its digits i.e. 5+1+6=12, is a multiple of 3. If the last two digits of a number are divisible by 4, then that number is a multiple of 4 and is divisible by 4 completely. Example: Take the number 2308. Consider the last two digits i.e. 08.
Can a number be divisible by 3 multiples?
As for divisibility by 3, there a neat trick to test for this: A number is divisible by 3 if and only if the sum of the digits is also a multiple of 3. The first two digits we already know are 9 and 5; 9 + 5 = 14. So the third digit has to be either 1, 4, or 7 to make the sum of the digits a multiple of 3.
Which is the divisibility rule for a number of 3?
Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3 i.e., it is a multiple of 3 Consider a number, 308. To check whether 308 is divisible by 3 or not, take sum of the digits (i.e. 3+0+8= 11). Now check whether the sum is divisible by 3 or not.
