Answer :23,46,69,92,115,138,161,184,207,230,253,276,299,322,345,368,391,414,437,460,483,506,529,552,575,598,621,644,667,690,713,736,759,782,805,828,851,874,897,920,943,966,989,1012,1035,1058,1081,1104,1127, Related Links : What are the factors of 23?
What are the first six multiples of 23?
The first 6 multiples of 23 are: 0, 23, 46, 69, 92, 115.
Are there any multiples for 23?
Solution: The first 5 multiples of 23 are, 23, 46, 69, 92, and 115. Sum of first 5 multiples of 5 = 23 + 46 + 69 + 92 + 115 = 345.
What can go into 23?
The factors of 23 are 1 and 23. Since 23 is a prime number, therefore, it has only two factors.
How many times can 3 go in 23?
There are 7 times 3 in 23. The answer you divide 23 by 3 which would get you 7.6666666666667.
Are there any numbers that are multiples of 3?
Multiples of 3. Any number that can be denoted in the form 3n where n is an integer is the multiples of 3. So if two values p and q are there, we say that q is a multiple of p if q = np for some integer n. Some of the multiples of 3 include, 6, 18, 21, 300, 60, etc.
How to find the multiples of a number?
So, the multiples of 7 are 7, 14, 21, 28, and so on. Note: The multiples of a number are obtained by multiplying the number by each of the natural numbers. For example: multiples of 2 are 2, 4, 6, 8, … multiples of 3 are 3, 6, 9, 12, … multiples of 4 are 4, 8, 12, 16, … Example 1 Write down the first ten multiples of 5. Solution:
How are the first five multiples of 9 obtained?
The multiples of 9 are obtained by multiplying 9 with the natural numbers 1, 2, 3, 4, 5. So, the first five multiples of 9 are 9, 18, 27, 36 and 45.
Which is the correct solution for multiples of 3 and 5?
15, 30, and all the common multiples of 3 and 5 will be summed twice. This can be be fixed by subtracting those common multiples. So a correct solution would be: S = S₃ + S₅ – (all common multiples of 3 and 5).
