1 is the lowest whole number that 6 and 8 are divisible by . I think you’re looking for the Lowest Common Multiple(LCM) of 6 and 8. To find LCM, take the larger grouping of each unique prime factor, and multiply it out. So LCM of 8 and 6 = 8 has 3 “2”s, and 6 has 1 “3”.
What is the smallest positive number divisible by 3 4 5 and 6?
Final answer: 9540. So 120 . Hence 120 is the smallest 3 digit number that is divisible by 3,4,5,6.
How do you find the factor of 235?
Getting factors is done by dividing 235 with numbers lower to it in value to find the one that will not leave remainder. Numbers that divide without remainders are the factors. Factors are whole numbers or integers that are multiplied together to produce a given number. The integers or whole numbers multiplied are factors of the given number.
Which is the smallest number with factor 3, 5?
Take 2, 6 and 8, for instance. Let N be the smallest number with 2, 6 and 8 as factors. N must have a 2*2*2, a 2*3 and a 2 in it. At the least, N has to be 2*2*2*3. In this arrangement, we find a 2, a 2*3 and a 2*2*2. So, N= 24.
Which is the smallest integer with exactly 16 factors?
We require that this product is 16 = 2 4. Thus, the only possible values for a k are 2 4 − 1 = 15, 2 3 − 1 = 7, 2 2 − 1 = 3, 2 − 1 = 1, 1 − 1 = 0. The partitions of 4 are The smallest number with 16 divisors is thus 120. Now we count up primes, and if there is a product of primes less than a prime we counted to, we inject it in before.
Which is the smallest prime to the sixth power?
Try to prove why!) Finally, as raising a number to the sixth power is a strictly increasing function, we conclude that the smallest sixth power of a prime must be the smallest prime to the sixth power. The solution is then 2 6 = 64. I hope you get something out of seeing this proof written carefully.
