28
The sum of all factors of 12 is 28.
What is the factor of 12000?
Factors of 12000 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 32, 40, 48, 50, 60, 75, 80, 96, 100, 120, 125, 150, 160, 200, 240, 250, 300, 375, 400, 480, 500, 600, 750, 800, 1000, 1200, 1500, 2000, 2400, 3000, 4000, 6000.
What are the factors of 18000?
Factors of 18000 are 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 25, 30, 36, 40, 45, 48, 50, 60, 72, 75, 80, 90, 100, 120, 125, 144, 150, 180, 200, 225, 240, 250, 300, 360, 375, 400, 450, 500, 600, 720, 750, 900, 1000, 1125, 1200, 1500, 1800, 2000, 2250, 3000, 3600, 4500, 6000, 9000.
What are all of the factors of 12000?
Factors of 12000 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 32, 40, 48, 50, 60, 75, 80, 96, 100, 120, 125, 150, 160, 200, 240, 250, 300, 375, 400, 480, 500, 600, 750, 800, 1000, 1200, 1500, 2000, 2400, 3000, 4000, 6000. There are 47 integers that are factors of 12000. The biggest factor of 12000 is 6000.
How to find the sum of all factors of 150?
All factors of 150 are 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150. Sum of all factors of 150 is (1 + 2 + 3 + 5 + 6 + 10 + 15 + 25 + 30 + 50 + 75 + 150) = 372. Since these numbers are smaller numbers, you get the sum of factors easily by adding all the factors of that number.
How to find the sum of all factors of 19600?
Ques 13: Find the sum of all factors of 19600. Solution : Prime Factorization of 19600 is 19600 = 2 4 x 5 2 x 7 2 Thus, the sum of all factors of 19600 is [(2 4+1 – 1)/(2 – 1)][(5 2+1 – 1)/(5 – 1)][(7 2+1 – 1)/(7 – 1)] = 54777.
How to calculate the sum of all factors of a number?
// This code is contributed by SanjuTomar. An efficient solution is to use below formula. Let p 1, p 2, … p k be prime factors of n. Let a 1, a 2, .. a k be highest powers of p 1, p 2, .. p k respectively that divide n, i.e., we can write n as n = (p1a1)* (p2a2)* … (pkak).
