Hence the sum of the first 8 multiples of 3 is 108.
What is the sum of multiple of 8?
| Number | Repeating Cycle of Sum of Digits of Multiples |
|---|---|
| 6 | {6,3,9,6,3,9,6,3,9} |
| 7 | {7,5,3,1,8,6,4,2,9} |
| 8 | {8,7,6,5,4,3,2,1,9} |
| 9 | {9,9,9,9,9,9,9,9,9} |
What is the sum of first 8 multiples of 8?
The sum of the first 15 multiples of 8 is 960….Thank you.
| Related Questions & Answers | |
|---|---|
| The Last Element Of Actinide Series Is | Virtual Value Or Effective Value Of A C Is |
What is the sum of first four multiples of 9?
Did you know that the sum of all the digits of the multiples of 9 add up to 9. For example, 18 is a multiple of 9 and 1 + 8 = 9. Similarly, 198 is a multiple of 9 and 1 + 9 + 8 = 18 and 1 + 8 = 9….List of First 20 Multiples of 9.
| Multiply 9 by the numbers from 1 to 20 | Multiples of 9 |
|---|---|
| 9 × 1 | 9 |
| 9 × 4 | 36 |
| 9 × 5 | 45 |
| 9 × 6 | 54 |
What is the sum of the first 8 multiples of 3?
Answer: The sum of the first 8 multiples of 3 is 108.
What is the sum of first five multiple of 8?
To get the fifth multiple of 8, we have to multiply 8 by 5 or add the number five times. Therefore, the fifth multiple of 8 is 8 x 5 = 40 or 8 + 8 + 8 + 8 + 8 = 40.
What is the sum of first 8 multiples of 3?
How to find the sum of first 15 multiples of 8?
Multiples of 8 are 8, 16, 24,…. Since difference is same, it is an AP We need to find sum of first 15 multiples We use formula Sn = �2 (2?+ (?−1)?) Here, n = 15, a = 8 & d = 16 – 8 = 8 Putting values in formula Sn = ?/2 (2?+ (?−1)?) = 15/2 (2×8+ (15−1)×8) = 15/2 (16+14×8) = 15/2 (16+112) = 15/2×128 = 960 Therefore.
How to calculate sum of digits for multiples of numbers?
These are shown below: Number Repeating Cycle of Sum of Digits of Mult 5 {5,1,6,2,7,3,8,4,9} 6 {6,3,9,6,3,9,6,3,9} 7 {7,5,3,1,8,6,4,2,9} 8 {8,7,6,5,4,3,2,1,9}
How to find the sum of the first 30 positive multiples of 3?
The one we will use is sn = n 2 (2a + (n − 1)d) n, or the number of terms, is 30. d, the common difference, is 3. a, the first term in the series is 3. Plugging these numbers into the formula, we get:
What is the sum of digits of adding 8 to 7?
Adding 8 to 7 results in a sum of digits of 6, and so on down to adding 8 to 1 which gives 9. Even this fits into the rule in the sense that if 1 were reduce by 1 the result would be 0 which is equivalent to 9 modulo 9. Likewise adding 7 to a digit reduces it by 3 and adds 1 to the digit in the next place, a net reduction in the sum of digits of 2.
