11 divided by 5 is 2 with a remainder of 1; 12 divided by 5 is 1 with a remainder of 2.
What is the smallest natural number that leaves a remainder of 2 when divided by 5 and a remainder of 14 when divided by 17?
Hence the answer is 62.
What is the smallest number that leaves a remainder of 2?
62 is the smallest number which gives 2 as reminder when divided by 3, 4, 5 and 6.
What is the smallest number when divided by 5 10 12 15 leaves remainder 2 in each case but divided by seven leaves nothing?
Step-by-step explanation: Then next multiple is 180. 182 is divisible by 7.
What is the least number which when divided by 8 12 15 and 18 leaves remainder 5 9 12 and 15 respectively?
Free Live Classes, Previous Year Papers, PDFs, Mocktests and more. The least number which is completely divisible by 8, 9, 12 and 15 will be the LCM of these numbers. ∴ The least number which when divided by 8, 9, 12 and 15, leaves the remainder 1 will be 360 + 1 = 361.
What is the smallest number of 3 and 15?
LCM of 3 and 15 by Listing Multiples Step 2: The common multiples from the multiples of 3 and 15 are 15, 30, . . . Step 3: The smallest common multiple of 3 and 15 is 15.
What would be the smallest natural number?
one
The smallest natural number is one. This comes from the definition of natural numbers, which are numbers that occur naturally for every day counting of a number of objects, such as twenty sheep in a field. The natural numbers are in the infinite class: [1,2,3,……………………] and are all positive.
Which is the smallest number that leaves a remainder of 2 when divided by 3/5 or 8?
Hence the least number which leaves remainder 2 when divided by 3, 5, 6, 8, 10 and 12 is 962. So, the correct answer is “Option B”. Note: Question asked that the least number there can be more than one number that can be divisible by numbers 3, 5, 6, 8, 10 and 12 and leaves the remainder 2.
Which is the smallest number with a remainder of 2?
The 6 is obsolete in this problem because 3 is already a factor of 6. Therefore testing each _2 number the first one (besides just 2) is 62. The next few numbers are: 122, 182, etc. 2 is the smallest one as 0*3 = 0*4 = 0*5 =0*6 = 0.
What is the smallest number that is divided by 35, 56, 91?
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647. 2) The number which is exactly divisible by 8, 15 and 21 = LCM of 8, 15 and 21. [The quotient when 110000 is divided by 840 is 13 and the remainder is 800.]
Is the number n divisible by a remainder?
The key to this is to realise that if a number N (eg 104) is to leave a remainder, say 4 when divided by 5 then N + 1 (ie 105) is exactly divisible by 5, similarly if a number (eg 87) is to leave a remainder 7 when divided by 8 then N + 1 (ie 88) is exactly divisible by 8:- Therefore in our question N + 1 is divisible by 2, 3, 4, 5, 6, 7, 8, 9 & 10
When do you get the remainder of a number?
When a number is divided by 2, 3, 4, 5 or 6, we always get a remainder of 1. But on dividing a number by 7, we find the number is divisible?
