The Principle of Zero Products states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0. Once the polynomial is factored, set each factor equal to zero and solve them separately. The answers will be the set of solutions for the original equation.
How do you factor a binomial that equals 0?
Set the equation equal to zero for each set of parentheses in the fully-factored binomial. For 2x^3 – 16 = 0, for example, the fully factored form is 2(x – 2)(x^2 + 2x + 4) = 0. Set each individual equation equal to zero to get x – 2 = 0 and x^2 + 2x + 4 = 0.
How do you factor 25x 2 16y2?
Rewrite 25×2 25 x 2 as (5x)2 ( 5 x ) 2 . Rewrite 16y2 16 y 2 as (4y)2 ( 4 y ) 2 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 – b 2 = ( a + b ) ( a – b ) where a=5x a = 5 x and b=4y b = 4 y .
Which is the factorised form of 2x + 2?
(2x +2)(x−6) is the factorised form of the expression. Explanation: 2×2 −10x −12 We can Split the Middle Term of 2×2-10x-12=0 Two solutions were found : x = 6 x = -1 Step by step solution : Step 1 :Equation at the end of step 1 : (2×2 – 10x) – 12 = 0 Step 2 : Step 3 :Pulling out like terms : …
How to solve 2×2-12x + 10 = 0?
2×2-12x+10=0 Two solutions were found : x = 5 x = 1 Step by step solution : Step 1 :Equation at the end of step 1 : (2×2 – 12x) + 10 = 0 Step 2 : Step 3 :Pulling out like terms : …
How to solve by factoring 2×2-11x + 12?
Solve by Factoring 2x^2-11x+12=0 2×2−11x+12=02×2-11x+12=0 Factorby grouping. Tap for more steps… For a polynomialof the form ax2+bx+cax2+bx+c, rewrite the middle termas a sumof two termswhose productis a⋅c=2⋅12=24a⋅c=2⋅12=24and whose sumis b=−11b=-11. Tap for more steps… Factor−11-11out of −11x-11x. 2×2−11x+12=02×2-11x+12=0
How to solve the equation 2 x 2 x 3?
Divide each term in 2 x = 3 2 x = 3 by 2 2. Cancel the common factor of 2 2. Tap for more steps… Cancel the common factor. Divide x x by 1 1. Set the next factor equal to 0 0 and solve. Tap for more steps… Set the next factor equal to 0 0. Add 4 4 to both sides of the equation.
